How to copy a java.util.List into another java.util.List

Just use this:

List<SomeBean> newList = new ArrayList<SomeBean>(otherList);

Note: still not thread safe, if you modify otherList from another thread, then you may want to make that otherList (and even newList) a CopyOnWriteArrayList, for instance -- or use a lock primitive, such as ReentrantReadWriteLock to serialize read/write access to whatever lists are concurrently accessed.


originalArrayList.addAll(copyArrayofList);

Please keep on mind whenever using the addAll() method for copy, the contents of both the array lists (originalArrayList and copyArrayofList) references to the same objects will be added to the list so if you modify any one of them then copyArrayofList also will also reflect the same change.

If you don't want side effect then you need to copy each of element from the originalArrayList to the copyArrayofList, like using a for or while loop. for deep copy you can use below code snippet.

but one more thing you need to do, implement the Cloneable interface and override the clone() method for SomeBean class.

public static List<SomeBean> cloneList(List<SomeBean> originalArrayList) {
    List<SomeBean> copyArrayofList = new ArrayList<SomeBean>(list.size());
    for (SomeBean item : list) copyArrayofList.add(item.clone());
    return copyArrayofList;
}

This is a really nice Java 8 way to do it:

List<String> list2 = list1.stream().collect(Collectors.toList());

Of course the advantage here is that you can filter and skip to only copy of part of the list.

e.g.

//don't copy the first element 
List<String> list2 = list1.stream().skip(1).collect(Collectors.toList());

I tried to do something like this, but I still got an IndexOutOfBoundsException.

I got a ConcurrentAccessException

This means you are modifying the list while you are trying to copy it, most likely in another thread. To fix this you have to either

  • use a collection which is designed for concurrent access.

  • lock the collection appropriately so you can iterate over it (or allow you to call a method which does this for you)

  • find a away to avoid needing to copy the original list.