How to check if running as root in a bash script

A few answers have been given, but it appears that the best method is to use is:

• id -u
• If run as root, will return an id of 0.

This appears to be more reliable than the other methods, and it seems that it return an id of 0 even if the script is run through sudo.

In a bash script, you have several ways to check if the running user is root.

As a warning, do not check if a user is root by using the root username. Nothing guarantees that the user with ID 0 is called root. It's a very strong convention that is broadly followed but anybody could rename the superuser another name.

I think the best way when using bash is to use $EUID, from the man page:

EUID   Expands to the effective user ID of the current  user,  initialized
       at shell startup.  This variable is readonly.

This is a better way than $UID which could be changed and not reflect the real user running the script.

if (( $EUID != 0 )); then
    echo "Please run as root"
    exit
fi

A way I approach that kind of problem is by injecting sudo in my commands when not run as root. Here is an example:

SUDO=''
if (( $EUID != 0 )); then
    SUDO='sudo'
fi
$SUDO a_command

This ways my command is run by root when using the superuser or by sudo when run by a regular user.

If your script is always to be run by root, simply set the rights accordingly (0500).

The $EUID environment variable holds the current user's UID. Root's UID is 0. Use something like this in your script:

if [ "$EUID" -ne 0 ]
  then echo "Please run as root"
  exit
fi

Note: If you get 2: [: Illegal number: check if you have #!/bin/sh at the top and change it to #!/bin/bash.