How do I print out the contents of a vector?

This solution was inspired by Marcelo's solution, with a few changes:

#include <iostream>
#include <iterator>
#include <type_traits>
#include <vector>
#include <algorithm>

// This works similar to ostream_iterator, but doesn't print a delimiter after the final item
template<typename T, typename TChar = char, typename TCharTraits = std::char_traits<TChar> >
class pretty_ostream_iterator : public std::iterator<std::output_iterator_tag, void, void, void, void>
{
public:
    typedef TChar char_type;
    typedef TCharTraits traits_type;
    typedef std::basic_ostream<TChar, TCharTraits> ostream_type;

    pretty_ostream_iterator(ostream_type &stream, const char_type *delim = NULL)
        : _stream(&stream), _delim(delim), _insertDelim(false)
    {
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator=(const T &value)
    {
        if( _delim != NULL )
        {
            // Don't insert a delimiter if this is the first time the function is called
            if( _insertDelim )
                (*_stream) << _delim;
            else
                _insertDelim = true;
        }
        (*_stream) << value;
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator*()
    {
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator++()
    {
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator++(int)
    {
        return *this;
    }
private:
    ostream_type *_stream;
    const char_type *_delim;
    bool _insertDelim;
};

#if _MSC_VER >= 1400

// Declare pretty_ostream_iterator as checked
template<typename T, typename TChar, typename TCharTraits>
struct std::_Is_checked_helper<pretty_ostream_iterator<T, TChar, TCharTraits> > : public std::tr1::true_type
{
};

#endif // _MSC_VER >= 1400

namespace std
{
    // Pre-declarations of container types so we don't actually have to include the relevant headers if not needed, speeding up compilation time.
    // These aren't necessary if you do actually include the headers.
    template<typename T, typename TAllocator> class vector;
    template<typename T, typename TAllocator> class list;
    template<typename T, typename TTraits, typename TAllocator> class set;
    template<typename TKey, typename TValue, typename TTraits, typename TAllocator> class map;
}

// Basic is_container template; specialize to derive from std::true_type for all desired container types
template<typename T> struct is_container : public std::false_type { };

// Mark vector as a container
template<typename T, typename TAllocator> struct is_container<std::vector<T, TAllocator> > : public std::true_type { };

// Mark list as a container
template<typename T, typename TAllocator> struct is_container<std::list<T, TAllocator> > : public std::true_type { };

// Mark set as a container
template<typename T, typename TTraits, typename TAllocator> struct is_container<std::set<T, TTraits, TAllocator> > : public std::true_type { };

// Mark map as a container
template<typename TKey, typename TValue, typename TTraits, typename TAllocator> struct is_container<std::map<TKey, TValue, TTraits, TAllocator> > : public std::true_type { };

// Holds the delimiter values for a specific character type
template<typename TChar>
struct delimiters_values
{
    typedef TChar char_type;
    const TChar *prefix;
    const TChar *delimiter;
    const TChar *postfix;
};

// Defines the delimiter values for a specific container and character type
template<typename T, typename TChar>
struct delimiters
{
    static const delimiters_values<TChar> values; 
};

// Default delimiters
template<typename T> struct delimiters<T, char> { static const delimiters_values<char> values; };
template<typename T> const delimiters_values<char> delimiters<T, char>::values = { "{ ", ", ", " }" };
template<typename T> struct delimiters<T, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T> const delimiters_values<wchar_t> delimiters<T, wchar_t>::values = { L"{ ", L", ", L" }" };

// Delimiters for set
template<typename T, typename TTraits, typename TAllocator> struct delimiters<std::set<T, TTraits, TAllocator>, char> { static const delimiters_values<char> values; };
template<typename T, typename TTraits, typename TAllocator> const delimiters_values<char> delimiters<std::set<T, TTraits, TAllocator>, char>::values = { "[ ", ", ", " ]" };
template<typename T, typename TTraits, typename TAllocator> struct delimiters<std::set<T, TTraits, TAllocator>, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T, typename TTraits, typename TAllocator> const delimiters_values<wchar_t> delimiters<std::set<T, TTraits, TAllocator>, wchar_t>::values = { L"[ ", L", ", L" ]" };

// Delimiters for pair
template<typename T1, typename T2> struct delimiters<std::pair<T1, T2>, char> { static const delimiters_values<char> values; };
template<typename T1, typename T2> const delimiters_values<char> delimiters<std::pair<T1, T2>, char>::values = { "(", ", ", ")" };
template<typename T1, typename T2> struct delimiters<std::pair<T1, T2>, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T1, typename T2> const delimiters_values<wchar_t> delimiters<std::pair<T1, T2>, wchar_t>::values = { L"(", L", ", L")" };

// Functor to print containers. You can use this directly if you want to specificy a non-default delimiters type.
template<typename T, typename TChar = char, typename TCharTraits = std::char_traits<TChar>, typename TDelimiters = delimiters<T, TChar> >
struct print_container_helper
{
    typedef TChar char_type;
    typedef TDelimiters delimiters_type;
    typedef std::basic_ostream<TChar, TCharTraits>& ostream_type;

    print_container_helper(const T &container)
        : _container(&container)
    {
    }

    void operator()(ostream_type &stream) const
    {
        if( delimiters_type::values.prefix != NULL )
            stream << delimiters_type::values.prefix;
        std::copy(_container->begin(), _container->end(), pretty_ostream_iterator<typename T::value_type, TChar, TCharTraits>(stream, delimiters_type::values.delimiter));
        if( delimiters_type::values.postfix != NULL )
            stream << delimiters_type::values.postfix;
    }
private:
    const T *_container;
};

// Prints a print_container_helper to the specified stream.
template<typename T, typename TChar, typename TCharTraits, typename TDelimiters>
std::basic_ostream<TChar, TCharTraits>& operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const print_container_helper<T, TChar, TDelimiters> &helper)
{
    helper(stream);
    return stream;
}

// Prints a container to the stream using default delimiters
template<typename T, typename TChar, typename TCharTraits>
typename std::enable_if<is_container<T>::value, std::basic_ostream<TChar, TCharTraits>&>::type
    operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const T &container)
{
    stream << print_container_helper<T, TChar, TCharTraits>(container);
    return stream;
}

// Prints a pair to the stream using delimiters from delimiters<std::pair<T1, T2>>.
template<typename T1, typename T2, typename TChar, typename TCharTraits>
std::basic_ostream<TChar, TCharTraits>& operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const std::pair<T1, T2> &value)
{
    if( delimiters<std::pair<T1, T2>, TChar>::values.prefix != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.prefix;

    stream << value.first;

    if( delimiters<std::pair<T1, T2>, TChar>::values.delimiter != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.delimiter;

    stream << value.second;

    if( delimiters<std::pair<T1, T2>, TChar>::values.postfix != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.postfix;
    return stream;    
}

// Used by the sample below to generate some values
struct fibonacci
{
    fibonacci() : f1(0), f2(1) { }
    int operator()()
    {
        int r = f1 + f2;
        f1 = f2;
        f2 = r;
        return f1;
    }
private:
    int f1;
    int f2;
};

int main()
{
    std::vector<int> v;
    std::generate_n(std::back_inserter(v), 10, fibonacci());

    std::cout << v << std::endl;

    // Example of using pretty_ostream_iterator directly
    std::generate_n(pretty_ostream_iterator<int>(std::cout, ";"), 20, fibonacci());
    std::cout << std::endl;
}

Like Marcelo's version, it uses an is_container type trait that must be specialized for all containers that are to be supported. It may be possible to use a trait to check for value_type, const_iterator, begin()/end(), but I'm not sure I'd recommend that since it might match things that match those criteria but aren't actually containers, like std::basic_string. Also like Marcelo's version, it uses templates that can be specialized to specify the delimiters to use.

The major difference is that I've built my version around a pretty_ostream_iterator, which works similar to the std::ostream_iterator but doesn't print a delimiter after the last item. Formatting the containers is done by the print_container_helper, which can be used directly to print containers without an is_container trait, or to specify a different delimiters type.

I've also defined is_container and delimiters so it will work for containers with non-standard predicates or allocators, and for both char and wchar_t. The operator<< function itself is also defined to work with both char and wchar_t streams.

Finally, I've used std::enable_if, which is available as part of C++0x, and works in Visual C++ 2010 and g++ 4.3 (needs the -std=c++0x flag) and later. This way there is no dependency on Boost.

A much easier way to do this is with the standard copy algorithm:

#include <iostream>
#include <algorithm> // for copy
#include <iterator> // for ostream_iterator
#include <vector>

int main() {
    /* Set up vector to hold chars a-z */
    std::vector<char> path;
    for (int ch = 'a'; ch <= 'z'; ++ch)
        path.push_back(ch);

    /* Print path vector to console */
    std::copy(path.begin(), path.end(), std::ostream_iterator<char>(std::cout, " "));

    return 0;
}

The ostream_iterator is what's called an iterator adaptor. It is templatized over the type to print out to the stream (in this case, char). cout (aka console output) is the stream we want to write to, and the space character (" ") is what we want printed between each element stored in the vector.

This standard algorithm is powerful and so are many others. The power and flexibility the standard library gives you are what make it so great. Just imagine: you can print a vector to the console with just one line of code. You don't have to deal with special cases with the separator character. You don't need to worry about for-loops. The standard library does it all for you.

If you have a C++11 compiler, I would suggest using a range-based for-loop (see below); or else use an iterator. But you have several options, all of which I will explain in what follows.

Range-based for-loop (C++11)

In C++11 (and later) you can use the new range-based for-loop, which looks like this:

std::vector<char> path;
// ...
for (char i: path)
    std::cout << i << ' ';

The type char in the for-loop statement should be the type of the elements of the vector path and not an integer indexing type. In other words, since path is of type std::vector<char>, the type that should appear in the range-based for-loop is char. However, you will likely often see the explicit type replaced with the auto placeholder type:

for (auto i: path)
    std::cout << i << ' ';

Regardless of whether you use the explicit type or the auto keyword, the object i has a value that is a copy of the actual item in the path object. Thus, all changes to i in the loop are not preserved in path itself:

std::vector<char> path{'a', 'b', 'c'};

for (auto i: path) {
    i = '_'; // 'i' is a copy of the element in 'path', so although
             // we can change 'i' here perfectly fine, the elements
             // of 'path' have not changed
    std::cout << i << ' '; // will print: "_ _ _"
}

for (auto i: path) {
    std::cout << i << ' '; // will print: "a b c"
}

If you would like to proscribe being able to change this copied value of i in the for-loop as well, you can force the type of i to be const char like this:

for (const auto i: path) {
    i = '_'; // this will now produce a compiler error
    std::cout << i << ' ';
}

If you would like to modify the items in path so that those changes persist in path outside of the for-loop, then you can use a reference like so:

for (auto& i: path) {
    i = '_'; // changes to 'i' will now also change the
             // element in 'path' itself to that value
    std::cout << i << ' ';
}

and even if you don't want to modify path, if the copying of objects is expensive you should use a const reference instead of copying by value:

for (const auto& i: path)
    std::cout << i << ' ';

Iterators

Before C++11 the canonical solution would have been to use an iterator, and that is still perfectly acceptable. They are used as follows:

std::vector<char> path;
// ...
for (std::vector<char>::const_iterator i = path.begin(); i != path.end(); ++i)
    std::cout << *i << ' ';

If you want to modify the vector's contents in the for-loop, then use iterator rather than const_iterator.

Supplement: typedef / type alias (C++11) / auto (C++11)

This is not another solution, but a supplement to the above iterator solution. If you are using the C++11 standard (or later), then you can use the auto keyword to help the readability:

for (auto i = path.begin(); i != path.end(); ++i)
    std::cout << *i << ' ';

Here the type of i will be non-const (i.e., the compiler will use std::vector<char>::iterator as the type of i). This is because we called the begin method, so the compiler deduced the type for i from that. If we call the cbegin method instead ("c" for const), then i will be a std::vector<char>::const_iterator:

for (auto i = path.cbegin(); i != path.cend(); ++i) {
    *i = '_'; // will produce a compiler error
    std::cout << *i << ' ';
}

If you're not comfortable with the compiler deducing types, then in C++11 you can use a type alias to avoid having to type the vector out all the time (a good habit to get into):

using Path = std::vector<char>; // C++11 onwards only
Path path; // 'Path' is an alias for std::vector<char>
// ...
for (Path::const_iterator i = path.begin(); i != path.end(); ++i)
    std::cout << *i << ' ';

If you do not have access to a C++11 compiler (or don't like the type alias syntax for whatever reason), then you can use the more traditional typedef:

typedef std::vector<char> Path; // 'Path' now a synonym for std::vector<char>
Path path;
// ...
for (Path::const_iterator i = path.begin(); i != path.end(); ++i)
    std::cout << *i << ' ';

Side note:

At this point, you may or may not have come across iterators before, and you may or may not have heard that iterators are what you are "supposed" to use, and may be wondering why. The answer is not easy to appreciate, but, in brief, the idea is that iterators are an abstraction that shield you from the details of the operation.

It is convenient to have an object (the iterator) that does the operation you want (like sequential access) rather than you writing the details yourself (the "details" being the code that does the actual accessing of the elements of the vector). You should notice that in the for-loop you are only ever asking the iterator to return you a value (*i, where i is the iterator) -- you are never interacting with path directly itself. The logic goes like this: you create an iterator and give it the object you want to loop over (iterator i = path.begin()), and then all you do is ask the iterator to get the next value for you (*i); you never had to worry exactly how the iterator did that -- that's its business, not yours.

OK, but what's the point? Well, imagine if getting a value wasn't simple. What if it involves a bit of work? You don't need to worry, because the iterator has handled that for you -- it sorts out the details, all you need to do is ask it for a value. Additionally, what if you change the container from std::vector to something else? In theory, your code doesn't change even if the details of how accessing elements in the new container does: remember, the iterator sorts all the details out for you behind the scenes, so you don't need to change your code at all -- you just ask the iterator for the next value in the container, same as before.

So, whilst this may seem like confusing overkill for looping through a vector, there are good reasons behind the concept of iterators and so you might as well get used to using them.

Indexing

You can also use a integer type to index through the elements of the vector in the for-loop explicitly:

for (int i=0; i<path.size(); ++i)
    std::cout << path[i] << ' ';

If you are going to do this, it's better to use the container's member types, if they are available and appropriate. std::vector has a member type called size_type for this job: it is the type returned by the size method.

typedef std::vector<char> Path; // 'Path' now a synonym for std::vector<char>
for (Path::size_type i=0; i<path.size(); ++i)
    std::cout << path[i] << ' ';

Why not use this in preference to the iterator solution? For simple cases, you can do that, but using an iterator brings several advantages, which I have briefly outlined above. As such, my advice would be to avoid this method unless you have good reasons for it.

std::copy (C++11)

See Joshua's answer. You can use the STL algorithm std::copy to copy the vector contents onto the output stream. I don't have anything to add, except to say that I don't use this method; but there's no good reason for that besides habit.

std::ranges::copy (C++20)

For completeness, C++20 introduced ranges, which can act on the whole range of a std::vector, so no need for begin and end:

#include <iterator> // for std::ostream_iterator
#include <algorithm> // for std::ranges::copy depending on lib support

std::vector<char> path;
// ...
std::ranges::copy(path, std::ostream_iterator<char>(std::cout, " "));

Unless you have a recent compiler (on GCC apparently at least version 10.1), likely you will not have ranges support even if you might have some C++20 features available.

Overload std::ostream::operator<<

See also Chris's answer below. This is more a complement to the other answers since you will still need to implement one of the solutions above in the overloading, but the benefit is much cleaner code. This is how you could use the std::ranges::copy solution above:

#include <iostream>
#include <vector>
#include <iterator> // for std::ostream_iterator
#include <algorithm> // for std::ranges::copy depending on lib support

using Path = std::vector<char>; // type alias for std::vector<char>

std::ostream& operator<< (std::ostream& out, const Path& v) {
    if ( !v.empty() ) {
        out << '[';
        std::ranges::copy(v, std::ostream_iterator<char>(out, ", "));
        out << "\b\b]"; // use two ANSI backspace characters '\b' to overwrite final ", "
    }
    return out;
}

int main() {
    Path path{'/', 'f', 'o', 'o'};

    // will output: "path: [/, f, o, o]"
    std::cout << "path: " << path << std::endl;

    return 0;
}

Now you can pass your Path objects to your output stream just like fundamental types. Using any of the other solutions above should also be equally straightforward.

Conclusion

Any of the solutions presented here will work. It's up to you (and context or your coding standards) on which one is the "best". Anything more detailed than this is probably best left for another question where the pros/cons can be properly evaluated, but as always user preference will always play a part: none of the solutions presented are objectively wrong, but some will look nicer to each coder.

Addendum

This is an expanded solution of an earlier one I posted. Since that post kept getting attention, I decided to expand on it and refer to the other excellent solutions posted here, at least those that I have personally used in the past at least once. I would, however, encourage the reader to look at the answers below because there are probably good suggestions that I have forgotten, or do not know, about.