How can I use grep to display lines WITHOUT either of two specific strings?

To remove lines that contain either string, specifically with grep:

• In one command, per jordanm's comment:

  grep -Ev 'success|ok$'
  

  or:

  grep -ve success -e 'ok$'
  

  or:

  grep -v 'success
  ok$'
  

• In two commands:

  grep -v success file | grep -v 'ok$'

Example:

$ cat file
success something else
success ok
just something else

$ grep -Ev 'success|ok$'
just something else
$ grep -v success file | grep -v 'ok$'
just something else

To remove lines that contain both strings, specifically with grep:

grep -v 'success.*ok$' file

Example:

$ cat file
success something else
success ok
just something else

$ grep -v 'success.*ok$' file
success something else
just something else

I would try awk

awk '/success/ { next ; } /ok$/ { next ; } { print ;}' file

where

• /success/ { next ; } find word success and skip line
• /ok$/ { next ; } find lower case ok and skip line
• { print ;} implicit else : print line

as per suggestion

short awk (thanks to Stéphane Chazelas )

awk '!/success/ && !/ok$/'

which is basically not (success) and not (ok at end of line )

golfed awk (thank to cas )

awk '! /success|ok$/'

which reuse regexp, and negate it