How can I simplify `(variableA && !variableB) || !variableA` expression in JavaScript?
(variableA && !variableB) || !variableA; if we use factoring to this result below
(!variableA || variableA) && (!variableA ||!variableB)
first part is always true then only second part is enough for u
!variableA ||!variableB
const variableA = 0;
const variableB = undefined;
console.log((variableA && !variableB) || !variableA); // true
console.log(!variableA ||!variableB);You could use
!(a && b)
or the equivalent with De Morgan's laws
!a || !b
const
f = (a, b) => (a && !b) || !a,
g = (a, b) => !(a && b),
h = (a, b) => !a || !b
console.log(0, 0, f(0, 0), g(0, 0), h(0, 0));
console.log(0, 1, f(0, 1), g(0, 1), h(0, 1));
console.log(1, 0, f(1, 0), g(1, 0), h(1, 0));
console.log(1, 1, f(1, 1), g(1, 1), h(1, 1));