google gson LinkedTreeMap class cast to myclass

EngineSense's answer is correct.
However, if you still want to use generics and don't want to pass in the concrete class type as a parameter here's an example of a workaround in Kotlin.
(Note that inline methods with reified type params cannot be called from Java).

May not be the most efficient way to get things done but it does work.


The following is in GsonUtil.kt

inline fun <reified T> fromJson(json: String): T? {
    return gson.fromJson(json, object : TypeToken<T>() {}.type)
}

fun <T> mapToObject(map: Map<String, Any?>?, type: Class<T>): T? {
    if (map == null) return null

    val json = gson.toJson(map)
    return gson.fromJson(json, type)
}

Method that retrieves a lightweight list of generic objects.

inline fun <reified T: MyBaseClass> getGenericList(): List<T> {
    val json = ...

    //Must use map here because the result is a list of LinkedTreeMaps
    val list: ArrayList<Map<String, Any?>>? = GsonUtil.fromJson(json)
    //handle type erasure
    val result = list?.mapNotNull {
        GsonUtil.mapToObject(it, T::class.java)
    }

    return  result ?: listOf()
}

Serializing and Deserializing Generic Types

When you call toJson(obj), Gson calls obj.getClass() to get information on the fields to serialize. Similarly, you can typically pass MyClass.class object in the fromJson(json, MyClass.class) method. This works fine if the object is a non-generic type. However, if the object is of a generic type, then the Generic type information is lost because of Java Type Erasure. Here is an example illustrating the point:

class Foo<T> {  T value;}
Gson gson = new Gson();
Foo<Bar> foo = new Foo<Bar>();
gson.toJson(foo); // May not serialize foo.value correctly
gson.fromJson(json, foo.getClass()); // Fails to deserialize foo.value as Bar

The above code fails to interpret value as type Bar because Gson invokes list.getClass() to get its class information, but this method returns a raw class, Foo.class. This means that Gson has no way of knowing that this is an object of type Foo, and not just plain Foo.

You can solve this problem by specifying the correct parameterized type for your generic type. You can do this by using the TypeToken class.

Type fooType = new TypeToken<Foo<Bar>>() {}.getType();    
gson.toJson(foo, fooType);
gson.fromJson(json, fooType);

I have Parent class and it's child class some of them having List types in it. Like this parent class i have 30 files. I solved it like this.

Gson gson = new Gson();
JSONObject jsonObj = new JSONObject(object.get(DO_SERVICES).toString());
Type type = new TypeToken<MyDto>() {}.getType();
servDto = gson.fromJson(jsonObj.toString(),type);

The most important thing is, I can't reproduce this error in local testing from Android studio. This problem pops up only, When i generate signed apk and publish app into PlayStore were the app stops, and the report says Cannot cast LinkedTreeMap to myclass.

It was hard for me to reproduce the same result in my local testing (includes Debug mode).

Tags:

Java

Android

Gson