Getting list of parameter names inside python function

Well we don't actually need inspect here.

>>> func = lambda x, y: (x, y)
>>> 
>>> func.__code__.co_argcount
2
>>> func.__code__.co_varnames
('x', 'y')
>>>
>>> def func2(x,y=3):
...  print(func2.__code__.co_varnames)
...  pass # Other things
... 
>>> func2(3,3)
('x', 'y')
>>> 
>>> func2.__defaults__
(3,)

For Python 2.5 and older, use func_code instead of __code__, and func_defaults instead of __defaults__.

locals() returns a dictionary with local names:

def func(a, b, c):
    print(locals().keys())

prints the list of parameters. If you use other local variables those will be included in this list. But you could make a copy at the beginning of your function.