Function pointer parameter without asterisk

Pointers to functions are peculiar. Given a function void f();, you can do

void (*fptr)() = f;
void (*fptr)() = &f;
void (*fptr)() = &&f;
void (*fptr)() = &&&f;

ad infinitum.

Similarly, when you call a function through a pointer to function you can do

fptr();
(*fptr)();
(**fptr)();
(***fptr)();

ad infinitum.

Everything collapses.

Standard says that these two functions are equivalent as function arguments are adjusted to be a pointer to function arguments:

16.1 Overloadable declarations [over.load]
(3.3) Parameter declarations that differ only in that one is a function type and the other is a pointer to the same function type are equivalent. That is, the function type is adjusted to become a pointer to function type (11.3.5).

same in C:

6.7.5.3 Function declarators (including prototypes)
8 A declaration of a parameter as ‘‘function returning type’’ shall be adjusted to ‘‘pointer to function returning type’’, as in 6.3.2.1.