For each day between two dates, add a row with the same info but only that day in the start/end columns

May be you need a Recursive CTE.

CREATE TABLE #dates(NAME  VARCHAR(50),START DATETIME,[END] DATETIME)

INSERT INTO #dates
VALUES      ('Bob','2014-10-30','2014-11-02')

DECLARE @maxdate DATETIME = (SELECT Max([end]) FROM   #dates);

WITH cte
     AS (SELECT NAME,
                START,
                [END]
         FROM   #dates
         UNION ALL
         SELECT NAME,
                Dateadd(day, 1, start),
                Dateadd(day, 1, start)
         FROM   cte
         WHERE  start < @maxdate)
SELECT *
FROM   cte 

OUTPUT :

name    START       END
----    ----------  ----------
Bob     2014-10-30  2014-10-30
Bob     2014-10-31  2014-10-31
Bob     2014-11-01  2014-11-01
Bob     2014-11-02  2014-11-02

You can do this with a recursive cte:

;with cte AS (SELECT Name,Start,[End]
              FROM YourTable
              UNION  ALL
              SELECT Name
                    ,DATEADD(day,1,Start)
                    ,[End]
              FROM cte
              WHERE Start < [End])
SELECT Name, Start, Start AS [End]
FROM cte

However, I suggest creating a calendar table and joining to it:

SELECT a.Name,b.CalendarDate AS Start, b.CalendarDate AS [End]
FROM YourTable a
JOIN tlkp_Calendar b
  ON b.CalendarDate BETWEEN a.[Start] AND a.[End]

Demo of both queries: SQL Fiddle