Finding Largest String in ArrayList

You can also use java.util.Collections.max or the Stream version:

Java 8

String max = Collections.max(strings, Comparator.comparing(String::length)); // or s -> s.length()

OR

String max = strings.stream().max(comparing(String::length)).get();

Prior Java 8

String max = Collections.max(Str, new Comparator<String>() {
    @Override
    public int compare(String o1, String o2) {          
        return o1.length() - o2.length();
    }
});     
    

Then

 System.out.println("Index " + arr.indexOf(max) + " " + max + " " + "is the largest and is size " + max.length());  

Please try these code . Here i am trying with get() to access the ArrayList elements, which is working correctly.

import java.util.Scanner;                  
import java.util.ArrayList;

class ArraylistString
{
    public static void main(String args[])
    {
        ArrayList<String> Str = new ArrayList<String>();
        Str.add("Jim Bob");
        Str.add("Bobby Jones");
        Str.add("Rob Stiles");
        int largestString = Str.get(0).length();
        int index = 0;

        for(int i = 0; i < Str.size(); i++)
        {
            if(Str.get(i).length() > largestString)
            {
                largestString = Str.get(i).length();
                                index = i;
            }
        }
        System.out.println("Index " + index + " "+ Str.get(index) + " " + "is the largest and is size " + largestString);  

    }

}