Euro coins and notes

Pure Bash, 48

s={1,2,5}
eval echo 0,0$s 0,${s}0 ${s}{,0,00},00

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-1 byte thanks to @Shaggy

5Æ#}ì ®eX-2 x2 d".,"
c

Returns an array of strings.

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print[('%.2f'%(10**(x/3-2)*(5>>~x%3))).replace(*'.,')for x in range(15)]

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The expression 5>>~x%3 maps the non-negative integers to 1, 2, 5, 1, 2, 5…

It works because 5, 2, 1 are the successive right-bitshifts of 5 (0b101 → 0b10 → 0b1); we cycle through them backwards.