Double Progress Bar in Python

I basically just want to add to the answer of @casper.dcl. In the slightly different case, where you have two nested for loops and want just a SINGLE progress bar you can do the following.

from tqdm import tqdm
import time
n = 5
m = 300
with tqdm(total=n * m) as pbar:
    for i1 in tqdm(range(n)):
        for i2 in tqdm(range(m)):
            # do something, e.g. sleep
            time.sleep(0.01)
            pbar.update(1)

I know that was not the question, but it might be still helpful for some folks.

Use enlighten:

import time
import enlighten

manager = enlighten.get_manager()
ticks = manager.counter(total=100, desc="Ticks", unit="ticks", color="red")
tocks = manager.counter(total=20, desc="Tocks", unit="tocks", color="blue")

for num in range(100):
    time.sleep(0.1)  # Simulate work
    print("The quick brown fox jumps over the lazy dog. {}".format(num))
    ticks.update()
    if not num % 5:
        tocks.update()

manager.stop()

It would require you to move the cursor position. I have written you a hacky thing to do it.

This script relies on the fact that the progressbar module assumes that you are on a fresh line to draw the progress bar. By simply moving the cursor up (using the escape code for "move cursor 1 row up"), and down (just using a newline. I could also use an escape code, but newline is easier and faster), one can maintain multiple progress bars.

import progressbar, time, sys

def up():
    # My terminal breaks if we don't flush after the escape-code
    sys.stdout.write('\x1b[1A')
    sys.stdout.flush()

def down():
    # I could use '\x1b[1B' here, but newline is faster and easier
    sys.stdout.write('\n')
    sys.stdout.flush()

# Total bar is at the bottom. Move down to draw it
down()
total = progressbar.ProgressBar(maxval=50)
total.start()

for i in range(1,51):
    # Move back up to prepare for sub-bar
    up()

    # I make a new sub-bar for every iteration, thinking it could be things
    # like "File progress", with total being total file progress.
    sub = progressbar.ProgressBar(maxval=50)
    sub.start()
    for y in range(51):
        sub.update(y)
        time.sleep(0.005)
    sub.finish()

    # Update total - The sub-bar printed a newline on finish, so we already
    # have focus on it
    total.update(i)
total.finish()

This is of course a bit hacky, but it gets the job done. I hope that it is useful.

Use the nested progress bars feature of tqdm, an extremely low overhead, very customisable progress bar library:

$ pip install -U tqdm

Then:

from tqdm import tqdm
# from tqdm.auto import tqdm  # notebook compatible
import time
for i1 in tqdm(range(5)):
    for i2 in tqdm(range(300), leave=False):
        # do something, e.g. sleep
        time.sleep(0.01)

(The leave=False is optional - needed to discard the nested bars upon completion.)

You can also use from tqdm import trange and then replace tqdm(range(...)) with trange(...). You can also get it working in a notebook.

Alternatively if you want just one bar to monitor everything, you can use tqdm's version of itertools.product:

from tqdm.contrib import itertools
import time
for i1, i2 in itertools.product(range(5), range(300)):
    # do something, e.g. sleep
    time.sleep(0.01)