Does the inverse command of cut exist?

As others have pointed out, you should not parse the output of ls. Assuming you are using ls only as an example and will be parsing something else, there are a few ways of doing what you want:

1. cut with -d and -f

   cut -d ' ' -f 1,2,3,4,9
   

   from man cut:

   -d, --delimiter=DELIM
         use DELIM instead of TAB for field delimiter
   
   -f, --fields=LIST
         select only these fields;  also print any line
         that contains no delimiter  character,  unless
         the -s option is specified
   

   Specifically for ls this is likely to fail since ls will change the amount of whitespace between consecutive fields to make them align better. cut treats foo<space>bar and foo<space><space>bar differently.

2. awk and its variants split each input line into fields on white space so you can tell it to print only the fields you want:

   awk '{print $1,$2,$3,$4,$9}'
   

3. Perl

   perl -lane 'print "@F[0 .. 3,8]"'
   

You can get the inverse of the results of cut by using the --complement option. The cut man page says (somewhat unhelpfully):

--complement

          complement the set of selected bytes, characters or fields

So, for instance,

$ echo The fifth and sixth words will be missing | cut -d ' ' -f 5-6 --complement The fifth and sixth be missing

Explanation:

• -d ' ' sets the delimiter to the space character
• -f 5-6 selects the fields 5 through 6 ("words will") to be output
• --complement returns the complement (inverse) of the selected text