Django order_by specific order

Since Django 1.8 you have Conditional Expressions so using extra is not necessary anymore.

from django.db.models import Case, When, Value, IntegerField

SomeModel.objects.annotate(
    custom_order=Case(
        When(id=5, then=Value(1)),
        When(id=2, then=Value(2)),
        When(id=3, then=Value(3)),
        When(id=1, then=Value(4)),
        When(id=4, then=Value(5)),
        output_field=IntegerField(),
    )
).order_by('custom_order')

It is possible. Since Django 1.8 you can do in the following way:

from django.db.models import Case, When

ids = [5, 2, 3, 1, 4]
order = Case(*[When(id=id, then=pos) for pos, id in enumerate(ids)])
queryset = MyModel.objects.filter(id__in=ids).order_by(order)