Django: Hide button in template, if user is not super-user

Check out is_superuser on the User object:

{% if request.user.is_superuser %}
    ...
    <button>...</button>
    ...
{% else %}
...
{% endif %}

EDIT: after @mustafa-0x comments

The above assumes that you have django.core.context_processors.request included in your TEMPLATE_CONTEXT_PROCESSORS setting which isn't the default.

The default setting for TEMPLATE_CONTEXT_PROCESSORS:

TEMPLATE_CONTEXT_PROCESSORS = (
    'django.contrib.auth.context_processors.auth',
    'django.core.context_processors.debug',
    'django.core.context_processors.i18n',
    'django.core.context_processors.media',
    'django.core.context_processors.static',
    'django.core.context_processors.tz',
#    'django.core.context_processors.request',
    'django.contrib.messages.context_processors.messages',
)

already includes the django.contrib.auth.context_processors.auth (and notably doesn't include the request context processor) meaning that in most cases you will already have access to {{ user }} without the need to add it to your context via the view, or enable the request context processor to access the user as above via {{ request.user }}


As discussed in the comments, you can use the User object that is available in templates automatically:

{% if user.is_superuser %}
<div class="alert alert-success" role="alert">
You are logged in as {{user.first_name}}, here are the
<a href="/admin/">admin pages</a> for changing content.
</div>
{% endif %}

You can also use user.is_staff which might be more appropriate.