Declaring Arrays In x86 Assembly

The AT&T syntax is used by the GNU assembler. The directive you're looking for is .fill <count>\[, <data-size>\[, <value>\]\]. In the specific case of 400 bytes:

array:  .fill  400

data-size defaults to 1 (byte). I believe the value that fills the 400 bytes defaults to zero.

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If you are actually using the nasm assembler (which is Intel format, not AT&T), then the times directive will work, as avinash indicated, as long as you want to predefine the data in either the .text or .data section. However, if you need to reserve bytes in the .bss section (in nasm), you can use the resb (reserve byte) directive:

       setion .bss
       ...
arr1   resb  400             ; Reserve 400 bytes (uninitialized)
arr2   times 400 resb 1      ;  Same thing, using times

Did you try TIMES directive.Use this code for declaring an array of a given size.

array TIMES 8 DB 0

This will create an array of size 8

Refer to this link for more.