Create batches in linq

You don't need to write any code. Use MoreLINQ Batch method, which batches the source sequence into sized buckets (MoreLINQ is available as a NuGet package you can install):

int size = 10;
var batches = sequence.Batch(size);

Which is implemented as:

public static IEnumerable<IEnumerable<TSource>> Batch<TSource>(
                  this IEnumerable<TSource> source, int size)
{
    TSource[] bucket = null;
    var count = 0;

    foreach (var item in source)
    {
        if (bucket == null)
            bucket = new TSource[size];

        bucket[count++] = item;
        if (count != size)
            continue;

        yield return bucket;

        bucket = null;
        count = 0;
    }

    if (bucket != null && count > 0)
        yield return bucket.Take(count).ToArray();
}

An Enumerable.Chunk() extension method was added to .NET 6.0.

Example:

var list = new List<int> { 1, 2, 3, 4, 5, 6, 7 };

var chunks = list.Chunk(3);
// returns { { 1, 2, 3 }, { 4, 5, 6 }, { 7 } }

For those who cannot upgrade, the source is available on GitHub.

public static class MyExtensions
{
    public static IEnumerable<IEnumerable<T>> Batch<T>(this IEnumerable<T> items,
                                                       int maxItems)
    {
        return items.Select((item, inx) => new { item, inx })
                    .GroupBy(x => x.inx / maxItems)
                    .Select(g => g.Select(x => x.item));
    }
}

and the usage would be:

List<int> list = new List<int>() { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };

foreach(var batch in list.Batch(3))
{
    Console.WriteLine(String.Join(",",batch));
}

OUTPUT:

0,1,2
3,4,5
6,7,8
9