Code Golf: What is the spaceship's fate? [floating point version]

Python, 178 170 chars

p=input
a,b,c,d=p()
x=a+b*1j
v=c+d*1j
P=(p(),p(),p())
R='escape'
for i in' '*10000:
 for a,b,g,r in P:
  d=a+b*1j-x;v+=g*d/abs(d)**3
  if abs(d)<r:R='crash'
 x+=v
print R

Golfrun/GolfScript?, 243 232 chars

10000:M;n%(','%2/{{~}%}/{{M*}%}:_~:v;_:x;'escape':R;{[','%2/{{~M*}%}/]}%:P;
M,{;P{~\x{0\-}%{+~@+@@+[\]}:|~:d.[~0\-]{[+.2%~*\.-2%~*@\-\.3%~*\(;);~*+]}:&~);~sqrt:z
..**\~d@[`~0]\&@M.*/\{1$/}%v|:v;;z\<{'crash':R;}{}if}/x v|:x;}/R puts

Golfrun is a language I'm working on, born as GolfScript C interpreter, but soon drifted away someway; though I've written this code without using knowingly specific Golfrun features (except for sqrt), the test with the original GolfScript failed (I had to add the sqrt feature to the original code, I am not a Ruby guru but I believe the problem is not my tweaking).

The first problem with this solution is that Golfrun, as GolfScript, has no floating point math. It is "simulated" magnifying the numbers, hopefully in the correct way (but I am not 100% confident I've done it coherently). Even so, the solution does not handle floating point numbers as input, so I had to magnify them by hand to have only integer numbers.

Trying to implement the algorithm in the Python code, I have also implemented bits of complex math in a rather "general" way. Manipulating the algorithm in order to avoid this, and/or inlining whenever possible, delaying the definitions, could save other chars...

How do I know this code works? Indeed, I am not sure it does! But giving the examples as input (after "removing" points where they appear), it wrote the expected results, except for the "corner case" (which raises an exception in Python too)...