Can someone explain how to append an element to an array in C programming?

You can have a counter (freePosition), which will track the next free place in an array of size n.

int arr[10] = {0, 5, 3, 64};
arr[4] = 5;

EDIT: So I was asked to explain what's happening when you do:

int arr[10] = {0, 5, 3, 64};

you create an array with 10 elements and you allocate values for the first 4 elements of the array.

Also keep in mind that arr starts at index arr[0] and ends at index arr[9] - 10 elements

arr[0] has value 0;
arr[1] has value 5;
arr[2] has value 3;
arr[3] has value 64;

after that the array contains garbage values / zeroes because you didn't allocated any other values

But you could still allocate 6 more values so when you do

arr[4] = 5;

you allocate the value 5 to the fifth element of the array.

You could do this until you allocate values for the last index of the arr that is arr[9];

Sorry if my explanation is choppy, but I have never been good at explaining things.

There are only two ways to put a value into an array, and one is just syntactic sugar for the other:

a[i] = v;
*(a+i) = v;

Thus, to put something as the element at index 4, you don't have any choice but arr[4] = 5.

For some people which might still see this question, there is another way on how to append another array element(s) in C. You can refer to this blog which shows a C code on how to append another element in your array.

But you can also use memcpy() function, to append element(s) of another array. You can use memcpy()like this:

#include <stdio.h>
#include <string.h>

int main(void)
{

int first_array[10] = {45, 2, 48, 3, 6};
int scnd_array[] = {8, 14, 69, 23, 5};
int i;

// 5 is the number of the elements which are going to be appended
memcpy(first_array + 5, scnd_array, 5 * sizeof(int));

// loop through and print all the array
for (i = 0; i < 10; i++) {
    printf("%d\n", a[i]);
  }

}