Can a sum of $n$ squares be expressed as the sum of $n/2$ squares?

The answer is yes for (even) $n \geq 8$ and no for (even) $n \leq 7$.

If $n \geq 8$ then the sum of your $n$ squares is the sum of four squares by the Lagrange four square theorem. Now, if $n/2$ is greater than 4, you can complete your sum by adding enough terms equal to $0^2$.

For $4 \leq n \leq 7$ note that $7$ can be written as the sum of $n$ squares but cannot be written as the sum of $n/2$ squares.

For $2 \leq n \leq 3$ note that $5$ is the sum of $n$ squares but not the sum of $n/2$ squares.