Button border with corner radius in Swift UI

Updated for Swift 5 & iOS 13.4+ with Press States!

None of the examples worked for buttons with both dark and white background colors as well as none of them had press state updates, so I built this LargeButton view that you can see below. Hope this helps, should be pretty simple to use!

Example Photos

enter image description here

Example Use

// White button with green border.
LargeButton(title: "Invite a Friend", 
            backgroundColor: Color.white, 
            foregroundColor: Color.green) {
                        print("Hello World")
                    }

// Yellow button without a border
LargeButton(title: "Invite a Friend", 
            backgroundColor: Color.yellow) {
                        print("Hello World")
                    }

Code

struct LargeButtonStyle: ButtonStyle {
    
    let backgroundColor: Color
    let foregroundColor: Color
    let isDisabled: Bool
    
    func makeBody(configuration: Self.Configuration) -> some View {
        let currentForegroundColor = isDisabled || configuration.isPressed ? foregroundColor.opacity(0.3) : foregroundColor
        return configuration.label
            .padding()
            .foregroundColor(currentForegroundColor)
            .background(isDisabled || configuration.isPressed ? backgroundColor.opacity(0.3) : backgroundColor)
            // This is the key part, we are using both an overlay as well as cornerRadius
            .cornerRadius(6)
            .overlay(
                RoundedRectangle(cornerRadius: 6)
                    .stroke(currentForegroundColor, lineWidth: 1)
        )
            .padding([.top, .bottom], 10)
            .font(Font.system(size: 19, weight: .semibold))
    }
}

struct LargeButton: View {
    
    private static let buttonHorizontalMargins: CGFloat = 20
    
    var backgroundColor: Color
    var foregroundColor: Color
    
    private let title: String
    private let action: () -> Void
    
    // It would be nice to make this into a binding.
    private let disabled: Bool
    
    init(title: String,
         disabled: Bool = false,
         backgroundColor: Color = Color.green,
         foregroundColor: Color = Color.white,
         action: @escaping () -> Void) {
        self.backgroundColor = backgroundColor
        self.foregroundColor = foregroundColor
        self.title = title
        self.action = action
        self.disabled = disabled
    }
    
    var body: some View {
        HStack {
            Spacer(minLength: LargeButton.buttonHorizontalMargins)
            Button(action:self.action) {
                Text(self.title)
                    .frame(maxWidth:.infinity)
            }
            .buttonStyle(LargeButtonStyle(backgroundColor: backgroundColor,
                                          foregroundColor: foregroundColor,
                                          isDisabled: disabled))
                .disabled(self.disabled)
            Spacer(minLength: LargeButton.buttonHorizontalMargins)
        }
        .frame(maxWidth:.infinity)
    }
}

Try it like this: Instead of setting the cornerRadius to the Button use an overlay for the inside View:

Edit: If you have a background for the button you also need to apply the cornerRadius to the background.

    Button(action: {
        print("sign up bin tapped")
    }) {
        Text("SIGN UP")
            .frame(minWidth: 0, maxWidth: .infinity)
            .font(.system(size: 18))
            .padding()
            .foregroundColor(.white)
            .overlay(
                RoundedRectangle(cornerRadius: 25)
                    .stroke(Color.white, lineWidth: 2)
        )
    }
    .background(Color.yellow) // If you have this
    .cornerRadius(25)         // You also need the cornerRadius here
    

Works for me. Let me know if it helps!


Official .bordered modifier support in iOS 15+

Buttons now have baked in border styling support using the .buttonStyle(.bordered) modifier. I would suggest using the corner radius Apple provides for these buttons for the best platform-specific styling. We can change the color to be consistent with the system styles for buttons and tint the background as well as text using the .tint modifier:

Button("Add") { ... }
.buttonStyle(.bordered)
.tint(.green)

Green Tint Buttons

You can make the tint color more prominent (bolder) using .borderedProminent and control the size using .controlSize:

Button("food") { ... }
.tint(.red)
.controlSize(.small) // .large, .medium or .small
.buttonStyle(.borderedProminent)

Small buttons

You can also use this modifier on parent Views of Buttons and toggle lighter color schemes using .accentColor in child Buttons:

ScrollView {
    LazyVStack {
        Button("Test Button 1") { ... }
        .buttonStyle(.borderedProminent)
        .keyboardShortcut(.defaultAction) // Tapping `Return` key actions this button

        Button("Test Button 2") { ... }
        .tint(.accentColor)
    }
}
.buttonStyle(.bordered)
.controlSize(.large)

Large Button Style

Advice

Apple for some reason doesn't like single-line bordered buttons which is why the .border() modifier was deprecated in Xcode 12. With this change, I suggest developers avoid creating single-line bordered buttons because they now are not preferred in Apple's Human Interface Guidelines. Using prominent buttons everywhere also violates HIG.

Extra NOTE: Apple's .bordered style provides the standard platform style across device types. In addition, the Button responds to Dark Mode dynamically and scales its size with Dynamic Type (native accessibility support).

Tags:

Ios

Swift

Swiftui