Batch file: Check if OS is Windows 10

I improved Vertexwahn's script to support more Windows versions:

setlocal
for /f "tokens=2 delims=[]" %%i in ('ver') do set VERSION=%%i
for /f "tokens=2-3 delims=. " %%i in ("%VERSION%") do set VERSION=%%i.%%j
if "%VERSION%" == "5.00" echo Windows 2000
if "%VERSION%" == "5.0" echo Windows 2000
if "%VERSION%" == "5.1" echo Windows XP
if "%VERSION%" == "5.2" echo Windows Server 2003
if "%VERSION%" == "6.0" echo Windows Vista
if "%VERSION%" == "6.1" echo Windows 7
if "%VERSION%" == "6.2" echo Windows 8
if "%VERSION%" == "6.3" echo Windows 8.1
if "%VERSION%" == "6.4" echo Windows 10
if "%VERSION%" == "10.0" echo Windows 10
echo %VERSION%
endlocal

if you want it a bit more detailed:

for /f "tokens=2 delims=," %%i in ('wmic os get caption^,version /format:csv') do set os=%%i
echo Hello, I am %os%

or to just meet your requirements:

for /f "tokens=2 delims=," %%i in ('wmic os get caption^,version /format:csv') do set os=%%i
echo %os%|find " 10 ">nul &&echo Hello I'm Windows 10||echo I am another os

(the ,version ensures, your desired string is not the last token, which contains that ugly wmic line ending)

setlocal
for /f "tokens=4-5 delims=. " %%i in ('ver') do set VERSION=%%i.%%j
if "%version%" == "6.3" echo Windows 8.1
if "%version%" == "6.2" echo Windows 8.
if "%version%" == "6.1" echo Windows 7.
if "%version%" == "6.0" echo Windows Vista.
if "%version%" == "10.0" echo Windows 10.
echo %version%
rem etc etc
endlocal