Alternate table row color using CSS?

You have the :nth-child() pseudo-class:

table tr:nth-child(odd) td{
    ...
}
table tr:nth-child(even) td{
    ...
}

In the early days of :nth-child() its browser support was kind of poor. That's why setting class="odd" became such a common technique. In late 2013 I'm glad to say that IE6 and IE7 are finally dead (or sick enough to stop caring) but IE8 is still around — thankfully, it's the only exception.


Just add the following to your html code (withing the <head>) and you are done.

HTML:

<style>
      tr:nth-of-type(odd) {
      background-color:#ccc;
    }
</style>

Easier and faster than jQuery examples.


$(document).ready(function()
{
  $("tr:odd").css({
    "background-color":"#000",
    "color":"#fff"});
});
tbody td{
  padding: 30px;
}

tbody tr:nth-child(odd){
  background-color: #4C8BF5;
  color: #fff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table border="1">
<tbody>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>6</td>
<td>7</td>
<td>8</td>
</tr>
<tr>
<td>9</td>
<td>10</td>
<td>11</td>
<td>13</td>
</tr>
</tbody>
</table>

There is a CSS selector, really a pseudo-selector, called nth-child. In pure CSS you can do the following:

tr:nth-child(even)
    background-color: #000000;
}

Note: No support in IE 8.

Or, if you have jQuery:

$(document).ready(function()
{
    $("tr:even").css("background-color", "#000000");
});